For i = 1 To 5
a(i) = Int(Rnd * 90) + 10
Next i
For j = 5 To 2 Step -1
If a(j) Mod 2 = 1 And a(j) < a(j - 1) Then
t = a(j): a(j) = a(j - 1): a(j - 1) = t
Else
a(j) = a(j) / 2
End If
Next j
执行该程序段后,a(1)到a(5)各元素不可能的是( )