用Cu
2S、FeS处理酸性废水中的Cr
2O
![](https://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmsubsup%3E%3Cmrow%3E%3C%2Fmrow%3E%3Cmn%3E7%3C%2Fmn%3E%3Cmrow%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3C%2Fmrow%3E%3C%2Fmsubsup%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
,发生的反应如下:
反应①:Cu2S+Cr2O
+H+→Cu2++SO
+Cr3++H2O(未配平)
反应②:FeS+Cr2O
+H+→Fe3++SO
+Cr3++H2O(未配平)
下列判断错误的是( )
- A、反应①中还原剂与氧化剂的物质的量之比为3:5
- B、用相同物质的量的Cu2S和FeS处理Cr2O
时,Cu2S消耗更多Cr2O ![](https://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmsubsup%3E%3Cmrow%3E%3C%2Fmrow%3E%3Cmn%3E7%3C%2Fmn%3E%3Cmrow%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3C%2Fmrow%3E%3C%2Fmsubsup%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
- C、处理等物质的量的Cr2O
时,反应①和②中消耗H+的物质的量相等 - D、用FeS处理废水不仅可以除去Cr2O
,还可吸附悬浮杂质