已知:NaHCO
3+NaOH
![](https://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmtable+columnalign%3D%22left%22%3E%3Cmtr+columnalign%3D%22left%22%3E%3Cmtd+columnalign%3D%22left%22%3E%3Cmunder+accentunder%3D%22true%22%3E%3Cmunder+accentunder%3D%22true%22%3E%3Cmrow%3E%3Cmtext%3E%CE%94%3C%2Fmtext%3E%3C%2Fmrow%3E%3Cmo+stretchy%3D%22true%22%3E_%3C%2Fmo%3E%3C%2Fmunder%3E%3Cmo+stretchy%3D%22true%22%3E_%3C%2Fmo%3E%3C%2Fmunder%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3Cmtr+columnalign%3D%22left%22%3E%3Cmtd+columnalign%3D%22left%22%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3C%2Fmtable%3E%3C%2Fmath%3E)
Na
2CO
3+H
2O,2NaHCO
3![](https://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmtable+columnalign%3D%22left%22%3E%3Cmtr+columnalign%3D%22left%22%3E%3Cmtd+columnalign%3D%22left%22%3E%3Cmunder+accentunder%3D%22true%22%3E%3Cmunder+accentunder%3D%22true%22%3E%3Cmrow%3E%3Cmtext%3E%CE%94%3C%2Fmtext%3E%3C%2Fmrow%3E%3Cmo+stretchy%3D%22true%22%3E_%3C%2Fmo%3E%3C%2Fmunder%3E%3Cmo+stretchy%3D%22true%22%3E_%3C%2Fmo%3E%3C%2Fmunder%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3Cmtr+columnalign%3D%22left%22%3E%3Cmtd+columnalign%3D%22left%22%3E%3C%2Fmtd%3E%3C%2Fmtr%3E%3C%2Fmtable%3E%3C%2Fmath%3E)
Na
2CO
3+CO
2↑+H
2O。现将一定质量的NaHCO
3、NaOH固体混合物,在密闭容器中加热至固体质量不再改变,剩余15.9g固体。将生成的气体全部通入足量澄清石灰水中,产生10.0g沉淀。下列说法正确的是( )
- A、剩余固体为混合物
- B、原固体加热共生成3.6gH2O
- C、原混合物中NaHCO3和NaOH的质量比为21:2
- D、取两份等质量的原混合物,一份直接与盐酸反应,另一份加热后再与盐酸反应,消耗HCl的质量不相等