a=['1','14','5141','91','9810']
key=input()
i=0;j=len(a)-1
while i<=j:
m=(i+j)//2
if a[m]==key:
break
elif a[m]<key:
i=m+1
else:
j=m-1
b=''
for i in range(len(a[m])):
b+=chr(ord(a[m][i])-49+97)
print(b)
已知ord(‘a’)的值为97,ord(‘1’)的值为49,若输入的key值为“1919810”,则程序运行后输出为( )