如图,已知∶ AB// EF,EP⊥EQ,∠EQC+∠APE=90°,求证∶ AB//CD
证明: AB// EF
∠APE= ▲ ( ▲ )
EP⊥EQ
∠PEQ= ▲ (垂直定义)即 ∠QEF+∠PEF = 90°
∠APE+∠QEF=90°
∵·∠EQC+∠APE=90°
∠EQC= ▲
EF// ▲ ( ▲ )
AB// CD( ▲ )