result="原点"
if x==0 or y==0:
result="数轴"
if x!=0 and y!=0:
result="象限"
elif x==0 and y==0:
else:
elif x==0 or y==0:
if x==0 and y==0:
n=int(input())
a=[0,0,0,0,0,0,0,0,0,0]
c=0
while n>0:
a[n%10]=a[n%10]+1
if a[n%10]==1:
c=c+1
n=n//10
print(c)
执行上述程序段,若输出c的值为4,则输入n的值可能为( )
s="13Ka5iSh79"
s1=""
for i in s:
if "0" <= i <= "9":
s1=i+s1
s1+=i
print(s1)
执行该程序段后,输出的结果是( )
s="VictoryOnTheWay" #'A'的ASCII值为65,"a"的ASCII码值为97
mx=""
pre=0
for i in range(1,len(s)):
if ord(s[i]) < 97:
if mx<s[pre:i]:
mx=s[pre:i]
pre=i
print(mx)( )
lst=[74,32,66,46,38,28,85]
k=1
for i in range(len(lst)-1):
if lst[i]*k < lst[i+1]*k:
print(lst[i],end=" ")
k=-k
执行完以上程序段后,输出的内容为( )
result=[]
i=0#用于遍历1st1
j=0#用于遍历1st2
while i<len(lst1) and j<len(lst2) :#①
if lst1[i]<lst2[j]:
result.append(lst1[i])
i+=1
result.append(lst2[j])
j+=1
while i<len(lst1):
result.append(lst1[i]) #②
while j<len(lst2):
result.append(lst2[j]) #③
下列说法不正确的是( )
from random import random
a=[1]*5
i=1
while i<=4:
a[i]=int(random()*10)+1
if a[i]==a[i-1]//2 or a[i]==a[i-1]*2:
执行该程序段后,数组a的值可能是( )
for i in range(n+1):
flag=False
if i%7==0:
flag=True
m=i
while :
if m%10==7:
m//=10
if :
sum=sum+i*i
print(sum)
编写程序,计算修改括号序列使其配对的最少次数。部分Python程序如下,请在划线处填入合适的代码。
s=input() #输入括号序列,序列中仅包含“(”、“)”两种字符,且长度为偶数
x=0
ans=0
for i in range(len(s)):
if s[i]=="(":
elif s[i]==")" and x>=1:
x-=1
elif s[i]==")" and :
ans+=1
x+=1
ans+=
print(ans)
比如:仓库存储情况列表a=["0","A","A","B","B","A","0","0","0"],其中"0"表示空位,"A","B"表示位置上货物种类,现需从中取出一件B货物,则应从右侧取出,取完后,仓库存储列表更新为a=["0","A","A","B","A","0","0","0","0"]。
请回答下列问题: