试题详情
某二元酸(H
2A)在水中的电离方程式为:H
2A=H
++HA
- , HA
-![](https://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmtext%3E%E2%87%8C%3C%2Fmtext%3E%3C%2Fmath%3E)
H
++A
2-![](https://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmrow%3E%3Cmo%3E%28%3C%2Fmo%3E%3Cmrow%3E%3Cmsub%3E%3Cmrow%3E%3Cmsub%3E%3Cmrow%3E%3Cmtext%3EK%3C%2Fmtext%3E%3C%2Fmrow%3E%3Cmrow%3E%3Cmtext%3Ea%3C%2Fmtext%3E%3C%2Fmrow%3E%3C%2Fmsub%3E%3C%2Fmrow%3E%3Cmrow%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmrow%3E%3C%2Fmsub%3E%3Cmo%3E%3D%3C%2Fmo%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmn%3E.%3C%2Fmn%3E%3Cmn%3E2%3C%2Fmn%3E%3Cmo%3E%C3%97%3C%2Fmo%3E%3Cmn%3E1%3C%2Fmn%3E%3Cmsup%3E%3Cmrow%3E%3Cmn%3E0%3C%2Fmn%3E%3C%2Fmrow%3E%3Cmrow%3E%3Cmo%3E%E2%88%92%3C%2Fmo%3E%3Cmn%3E2%3C%2Fmn%3E%3C%2Fmrow%3E%3C%2Fmsup%3E%3C%2Fmrow%3E%3Cmo%3E%29%3C%2Fmo%3E%3C%2Fmrow%3E%3C%2Fmath%3E)
, 下列说法错误的是( )
- A、在0.1 mol/L的Na2A溶液中,c(A2-)+c(HA-)+2c(Na+)=0.5 mol/L
- B、25℃时,若测得0.1 mol/L的NaHA溶液pOH=a,升高温度,测得同浓度的NaHA溶液pOH=b,则b一定大于a
- C、25℃时,将同浓度的NaHA和Na2A溶液等体积混合,其pH一定小于7
- D、0.1 mol/L的NaHA溶液中离子浓度为:c(Na+)>c(HA-)>c(H+)>c(A2-)>c(OH-)
知识点
参考答案