已知：Fe₂O₃(s)＋3C(石墨)= 2Fe(s)＋3CO(g)  ΔH＝＋489.0 kJ·mol⁻¹①

CO(g)＋ O₂(g)= CO₂(g)  ΔH＝−283.0 kJ·mol⁻¹②

C(石墨)＋O₂(g)= CO₂(g)  ΔH＝−393.5 kJ·mol⁻¹③

则4Fe(s)＋3O₂(g)= 2Fe₂O₃(s)的ΔH为(　　)

A、＋1 164.1 kJ·mol⁻¹

B、−1 641.0 kJ·mol⁻¹

C、−259.7 kJ·mol⁻¹

D、−519.4 kJ·mol⁻¹